4 Queens Poker Room

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Binion’s was once home to the World Series of Poker. It lost poker’s main tournament series in 2005 after the casino was acquired by Harrah’s Entertainment, which is known today as Caesars Entertainment. This started a freefall for Binion’s relevance in the poker scene.

  1. 4 Queens Poker Room Layout
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The poker room gives players $2 per hour in comps. Cash game and tournament players receive free parking. Comps may be used for food on the property or at the Four Queens hotel. Although the hotel rooms at Binion’s have been closed since 2009, poker players do receive a discounted room rate at Four Queens. This is a sister property of Binion’s. Book Four Queens Hotel and Casino, Las Vegas on Tripadvisor: See 3,072 traveller reviews, 1,081 candid photos, and great deals for Four Queens Hotel and Casino, ranked #110 of 282 hotels in Las Vegas and rated 3.5 of 5 at Tripadvisor. Prices are calculated as of 2020-12-07 based on a.

The casino is now owned by TLC Enterprises. This is the same company that owns Four Queens. Many changes have occurred on the property since Binion’s changed hands. Its hotel closed, valet service was discontinued, and players must now earn free parking on visits.

The quality of casino games has since fallen off a cliff. All blackjack tables there now pay 6 to 5. The best video poker game has a house edge of nearly one percent.

Binion’s once spread dozens of poker tables. There was a cash game section near the front of the casino. A tournament section was found at the rear of the casino where the hotel’s front desk was once located. The cash game section is now occupied by virtual table games. The tournament section is now a retail area with some historical memorabilia to its better days.

In 2017, Binion’s moved its poker room. It is now found at the rear of the table game pit. It now hosts just six poker tables. This is ample space during most times of the year. The capacity is generally only needed for the summer Binion’s Poker Jam and an occasional weekend guaranteed tournament.

It is rare to find more than one cash game table at Binion’s and the tournament action is slow. This is a significant drop from its business just a few years ago. Most of the Downtown Las Vegas poker action is now at Golden Nugget.

Best and Worst Features of Binion’s Poker Room

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The best part of playing poker at Binion’s is its deep poker history. Many of the dealers from the peak years are still around. This means the games have a high level of professionalism. The sportsbook and restrooms are just a few steps away.

It is difficult to find a game here these days. When one does run, the games tend to be tight and full of regulars. The tournaments tend to only draw one or two tables, if they get off the ground at all. The room is more like a pit. This can make it smoky from nearby table games, slots, and the sportsbook.

The only regular cash game at Binion’s is 1/2 no-limit Texas Hold’em. The minimum buy-in is $100. There is no cap.

Binion’s advertises a fixed-limit game, but this has not been a regular fixture there in years.

Binion’s rakes 10% up to $4 per hand plus a jackpot drop. The poker room gives players $2 per hour in comps.

Cash game and tournament players receive free parking. Comps may be used for food on the property or at the Four Queens hotel.

Although the hotel rooms at Binion’s have been closed since 2009, poker players do receive a discounted room rate at Four Queens. This is a sister property of Binion’s.

Binion’s offers a $45+$15 tournament every day at 1 pm and 6 pm. This tournament has $20 re-buys and add-ons. Players start with 10,000 in chips. The first level is 50/100. Limits go up every 20 minutes.

The schedule varies on Saturdays. The 1 pm tournament has a $120+$30 buy-in. The starting stack is 20,000 chips. The first level is 50/100. Limits go up every 30 minutes. This tournament does not have re-buys or add-ons.

There is a summer tournament series that runs during the same time as the World Series of Poker. It is called the Dog Days of Summer Poker Series. The buy-ins tend to be from $200 to $1,000. There is a wide variety of games spread during this event. In addition to no-limit Hold’em, players will find pot-limit Omaha, pot-limit Omaha Hi/Lo, fixed-limit Omaha Hi/Lo, as well as stud and mixed games.

Binion’s offers poker promotions that rotate. These are typically high hand bonuses.

The hotel accommodation offer mentioned earlier comes with no minimum play requirement. For full details on this offer, you can call 702-366-7361. It tends to about $29 on weeknights and $60 on weekends.

The only non-gaming amenity at Binion’s is restaurants. The Top of Binion’s Steakhouse is a hidden gem downtown. Guests may access it through a glass elevator that overlooks the Fremont Street Experience. Otherwise, there is a café and deli.

There is plenty to do outside of Binion’s. The Fremont Street Experience offers light shows at the top of every hour at night on its canopy. There are bands playing outside Binion’s each evening.

During the summer, classic bands perform. One of the biggest parties in the world takes place on New Year’s Eve at the Fremont Street Experience. There is a zip line that cruises the length of it that operates day and night year-round.

Golden Nugget is the only other poker room left in Downtown Las Vegas. It offers 1/2 no-limit Hold’em with the same $100 minimum as Binion’s. There is also no cap in this game. Players will find fixed-limit Hold’em at Golden Nugget, too. The casinos are across from each other on the Fremont Street Experience.

If you are looking for tournaments, Golden Nugget is a great choice. Like Binion’s, it has a summer tournament series.

The series includes at least two daily events with many non-Hold’em tournaments. Golden Nugget spreads four daily tournaments each day. The buy-in is $50 at 3 pm and 10 pm and $70 at 11 am and 7 pm. On Sundays at 11 am, Golden Nugget spreads a $125 tournament with a $5,000 guaranteed prize pool.

The only other poker room close to Binion’s is at Stratosphere. It struggles with cash game and tournament traffic in the same way Binion’s does. We feel you are better off checking out the action at Golden Nugget if you are not happy with the play at Binion’s.

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6 members have voted

unJon

This could easily be wrong, but here is where I'm at with the four-vendor case:
Vendor 1 picks a spot a smidge to the left of 0.1
Vendor 2 picks a spot a smidge to the right of 0.9
Vendor 3 will be indifferent between 0.4 and 0.6. Let's just say he picks 0.4
Vendor 4 will pick 0.65.
This would give space as follows:
Vendor 1 0.25
Vendor 2 0.275
Vendor 3 0.25
Vendor 4 0.225
However, Vendor 3 could pick the spot closer to vendor 2. It would average out to:
Vendor 1 0.2375
Vendor 2 0.2750
Vendor 3 0.2500
Vendor 4 0.2375
Thoughts?

Let’s try a simplifying assumption. A and B will want to be at the lowest and highest spots because tending too far away from an end leave them open to C and D grabbing that territory that is unshared to the beach ends. A and B will pick spots such that the distance to the island end is half the distance that C and D could claim in the middle (since middle beach territory only runs to the midpoint to the next vendor).
If that holds let’s run a test where A goes to 1/5 mile mark. If 3 vendors means A goes to 1/4, then maybe it’s as simple as A going to 1/(1+n)? And B responds by going to 4/5 mile marker.
C will want to make D indifferent about going to the left or right of him. That means C will go to 1/2 and D will land a smidge to the right or left of C. This is generally true of a two vendor problem, which is exactly what the four vendor problem reduces to (since A and B simply “shrink” the useable end points of the beach). C and D capture territory of (1/2 - 1/5) / 2 = 3/20.
Since 3/20 territory is worse than D could have done by cutting A or B off from the end (capturing 1/5 or 4/20), that means A and B are too far from the island edge.
The indifference equation then is A - 0 = (1/2 - A)/2. So A should equal 1/6.
So A goes to 1/6 (or a smidge less), B goes to 5/6 (or a smidge more), C goes a smidge to the left (or right) of 1/2 and D takes the middle.
Poker
Looks like my answer agrees with Charliepatrick’s.
The race is not always to the swift, nor the battle to the strong; but that is the way to bet.
charliepatrick

...C goes a smidge....

4 Queens Poker Room

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Last night I wasn't sure why C would go to the middle. In the two vendor case whereever C goes D goes next door. However in this case D is indifferent where he goes on the segment, except it will be the larger segment remaining, as the other end is shared with A or B. In fact D gets half the segment between C and either A or B.
Thus if C leaves a larger segment on one side then D gets a larger slice than C going in the middle. It didn't seem obvious this would be to the detriment of C.
For argument's sake (since we're looking at C) look at various points where C is nearer to A. C will share that segment so has a AC/2 slice.
D picks a point randomly between C and B, so on average CD = CB/2. Thus C's slice is CB/4. The total of the two slices is (AC/4+AC/4)+CB/4=AC/4+AB/4. Thus C should maximise AC and pick the middle.
unJon
Thanks for this post from:
Last night I wasn't sure why C would go to the middle. In the two vendor case whereever C goes D goes next door. However in this case D is indifferent where he goes on the segment, except it will be the larger segment remaining, as the other end is shared with A or B. In fact D gets half the segment between C and either A or B.
Thus if C leaves a larger segment on one side then D gets a larger slice than C going in the middle. It didn't seem obvious this would be to the detriment of C.
For argument's sake (since we're looking at C) look at various points where C is nearer to A. C will share that segment so has a AC/2 slice.
D picks a point randomly between C and B, so on average CD = CB/2. Thus C's slice is CB/4. The total of the two slices is (AC/4+AC/4)+CB/4=AC/4+AB/4. Thus C should maximise AC and pick the middle.
That makes sense to me.
The race is not always to the swift, nor the battle to the strong; but that is the way to bet.
Wizard
Administrator

Looks like my answer agrees with Charliepatrick’s.


I agree and stand corrected.
It's not whether you win or lose; it's whether or not you had a good bet.
Wizard
Administrator
How about the case of n pirates? Let's think of it in terms of units of space, as opposed to 1 mile.

The first two vendors to act will pick spots a smidge less than 1 unit from either edge.
Vendors 3 to n-2 will pick spots 2 minus a smidge units away from already established vendor
Vendor n-1 will pick a spot exactly between the closest vendors in the progressions from each end.
Vendor n will be indifferent between the spot exactly between n-1 and one of the vendors to his side, because he will get a full unit, as opposed to one unit minus a smidge.
At the end of the day:
Vendors 1 and 2 will get 1.5 units of space
Vendors 3 to n-4 will get 1 unit each
Vendors n-2 and n-3 will get 1 and 1.5 units each. Who gets how much will depend on n's action.
Vendor n-1 will get 1.5 units
Vendor n will get 1 unit.
p.s. Why doesn't my spell checker like 'smidge?'
p.p.s Do I put the question mark inside or outside the right quote?
It's not whether you win or lose; it's whether or not you had a good bet.
unJon

How about the case of n pirates. Let's think of it in terms of units of space, as opposed to 1 mile.


The first two vendors to act will pick spots a smidge less than 1 unit from either edge.
Vendors 3 to n-2 will pick spots 2 minus a smidge units away from already established vendor
Vendor n-1 will pick a spot exactly between the closest vendors in the progressions from each end.
Vendor n will be indifferent between the spot exactly between n-1 and one of the vendors to his side, because he will get a full unit, as opposed to one unit minus a smidge.
At the end of the day:
Vendors 1 and 2 will get 1.5 units of space
Vendors 3 to n-4 will get 1 unit each
Vendors n-2 and n-3 will get 1 and 1.5 units each. Who gets how much will depend on n's action.
Vendor n-1 will get 1.5 units
Vendor n will get 1 unit.
p.s. Why doesn't my spell checker like 'smidge?'
p.p.s Do I put the question mark inside or outside the right quote?

1) Pirates on the brain! :-)
2) I’d put the ? Outside the quotes there.4 Queens Poker Room
The race is not always to the swift, nor the battle to the strong; but that is the way to bet.
Ayecarumba

How about the case of n pirates? Let's think of it in terms of units of space, as opposed to 1 mile.


The first two vendors to act will pick spots a smidge less than 1 unit from either edge.
Vendors 3 to n-2 will pick spots 2 minus a smidge units away from already established vendor
Vendor n-1 will pick a spot exactly between the closest vendors in the progressions from each end.
Vendor n will be indifferent between the spot exactly between n-1 and one of the vendors to his side, because he will get a full unit, as opposed to one unit minus a smidge.
At the end of the day:
Vendors 1 and 2 will get 1.5 units of space
Vendors 3 to n-4 will get 1 unit each
Vendors n-2 and n-3 will get 1 and 1.5 units each. Who gets how much will depend on n's action.
Vendor n-1 will get 1.5 units
Vendor n will get 1 unit.
p.s. Why doesn't my spell checker like 'smidge?'
p.p.s Do I put the question mark inside or outside the right quote?

What if none of the vendors knows n? Will vendor 1 set up in the middle of the strand?
Simplicity is the ultimate sophistication - Leonardo da Vinci
charliepatrick

King Queen Poker

What if none of the vendors knows n? Will vendor 1 set up in the middle of the strand?

I'd guess the correct logic is the first person goes in the middle and the rest just go in the middle of the largest gap left. Thus three people would be at 25% 50% and 75%, seven at 1/8 2/8... 7/8 etc.
Wizard
Administrator

What if none of the vendors knows n? Will vendor 1 set up in the middle of the strand?


They know what n is.
It's not whether you win or lose; it's whether or not you had a good bet.
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99kv99

Little Kings And Queens Poker

1/(2n-2)?